# Bomba
The challenge instructions come with everything we need to successfully decipher the encrypted message:

and

```
UCF 07 ZERO 0800 = 50 = MHW FLC = LWB VJT LWD QYB JMS AMU RBO QXY SBZ EYN RLG RNK KVQ YJK EKR GMS CYB MH=
```

The first part is not really of interest. ```50``` indicates the length of the message, ```MHW``` is the initial rotor position, ```FLC``` is the encrypted message key value and the first 3-character block of the last part, ``` LWB ```, is the Kenngruppen value which determines the rotor-, reflector-, ring- and plugboard-settings for the day. ```LWB``` is a Kenngruppen value of day 7. Everything behind it is the actual ciphertext. Now we can just look up day 7 in the table and initialize our Enigma with these settings.

Note: Don't forget to remove ```LWB``` from the ciphertext in order to decrypt the message correctly.

```
from enigma.machine import EnigmaMachine

machine = EnigmaMachine.from_key_sheet(
rotors = 'V I IV',
reflector = 'B',
ring_settings = [18, 11, 25],
plugboard_settings = 'TS IK AV QP HW FM DX NG CY UE')

ciphertext = 'VJTLWDQYBJMSAMURBOQXYSBZEYNRLGRNKKVQYJKEKRGMSCYBMH'

machine.set_display('MHW') # set initial rotor position
msg_key = machine.process_text('FLC') # decrypt the message key value
machine.set_display(msg_key)
plaintext = machine.process_text(ciphertext)

print(plaintext)
```

Output: DAMNXTHATXBOMBAXKRYPTOLOGICZNAXANDXMARIANXREJEWSKI

## sun{DAMNXTHATXBOMBAXKRYPTOLOGICZNAXANDXMARIANXREJEWSKI}