**Attachment**:
- https://static.n00bzunit3d.xyz/Crypto/Vinegar2/chall.py
- https://static.n00bzunit3d.xyz/Crypto/Vinegar2/enc.txt

We were provided with a script to encrypt content of a flag to ciphertext and a ciphertext

And since we already got a key and know which encryption that was using, we can write a new script to reverse it back to plaintext like this

```
alphanumerical = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890!@#$%^&*(){}_?'
matrix = []
for i in alphanumerical:
matrix.append([i])

idx=0
for i in alphanumerical:
matrix[idx][0] = (alphanumerical[idx:len(alphanumerical)] + alphanumerical[0:idx])
idx += 1

key = '5up3r_s3cr3t_k3y_f0r_1337h4x0rs_r1gh7?'
ciphertext = '*fa4Q(}$ryHGswGPYhOC{C{1)&_vOpHpc2r0({'

assert len(key) == len(ciphertext)

key_arr = []
for y in key:
for i in range(len(alphanumerical)):
if matrix[i][0][0] == y:
key_arr.append(i)

dec_arr = []
for i in range(len(ciphertext)):
char = ciphertext[i]
key_index = key_arr[i]
for j in range(len(alphanumerical)):
if matrix[j][0][key_index] == char:
dec_arr.append(matrix[j][0][0])
break

decrypted_flag = ''.join(dec_arr)
print(decrypted_flag)
```


Execute it to get a flag

```
n00bz{4lph4num3r1c4l_1s_n0t_4_pr0bl3m}
```

Original writeup (https://github.com/ChickenLoner/Write-Up/blob/main/Unlisted%20Labs/n00bz%20CTF%202024%20Write-up%20(ByTheW4y%20Team).md).