Simply reversing encrypt order we can get easy flag. Here is a working example - [https://ideone.com/LLxa3j](https://ideone.com/LLxa3j)

```python
#!/usr/bin/env python3

from random import *
from Crypto.Util.number import *

def decrypt(msg, KEY):
c = KEY ^ m
return long_to_bytes(c)

m = 2290064970177041546889165766737348623235283630135906565145883208626788551598431732
k = 23226475334448992634882677537728533150528705952262010830460862502359965393545
print(decrypt(m, k))
```

> MAPNA{R_U_MT19937_PRNG_Predictor?}